Need Help 2. Given: Pa(s) + 3 O2(g) → P.O(s) AH = -1640.1 kJ Pa(s) +...
Given: P4(s) + 3 O2(g) --> P406(s) ?H = -1640.1 kJ P4(s)+ 5 O2(g)--> P4O10(s). ?H=-2940.1 kJ Use Hess Law to calculate the ?H for P4O6(s) + 2O2(g)-->P4O10(s)
Given the following data: 3 s(s) + 2O2(9) S03(9) AH = -395.2 kJ 2802(g) + O2(g) +2503(9) AH = - 198.2 kJ Calculate AH for the reaction: S(s) + O2(g) → SO2(g) +296.1 kJ -197.0 kJ -296.1 kJ -593.4 kJ -494.3 kJ
Given: NO (g) + O2(g) +2 NO2 (g) AH = -114.2 kJ Calculate AH for this equation: 2 NO(g) + 2O2(g) →4 NO2 (g) Note: Your answer should be in kJ
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C3H8(g) + 5 O2(g) = 3 CO2(g) + 4H2O(1) AH = -2220 kJ Decreasing the temperature will result in shift the equilibrium to the right shift the equilibrium to the left Keq is decreased O no effect in shifting the equilibrium more information is needed Which of the following expressions is the correct equilibrium-constant expression for the reaction below? P4010(s) = P4(s) + 5 O2(g) [02]-5 O [0215 [P4010] [Pd][02] [P][0215 O [P4010] [P4010) [P][0,1175 A proposed...
AH = -727 kJ Given that CH3OH (1) + 3/2 O2 (g) → CO2 (g) + 2 H2O(1) CO(g) + 1/2O2 (g) → CO2 (9) CH3OH(1) → CH3OH(g) AH = -284 kJ AH = 38 kJ H20 (1)→ H20 (9) AH = 44 kJ what is AH, in kJ, for the reaction CH3OH (g) + O2(g) →CO (g) + 2 H2O (9)
Problem Solving: Show all work, units, sie fies and balanced equations needed to answer the following 1. To make the hydrogen necessary for the manufacture of ammonia in the Haber/Bosch process a steam reforming method is used. This method combines methane gas with steam (water gas) to make hydrogen gas and carbon monoxide gas. The AH for this reaction is + 206 kJ/mole. What amount of energy is needed to produce 1 kg of hydrogen? 2. Given: P.(s) + 3...
I especially need help with understanding what the second
question is asking.
4. Use Hess' Law to calculate the enthalpy change (AHⓇt) for this reaction: (12 pts.) 6C(s) + 6H2(g) + 3029) → C6H12O6(S) + using the following equations: A. C(s) + O2(g) → CO2(g) B. H2(g) + 1/2O2(g) → H2O(g) C. C6H12O6(s) + 6020) — 6CO2(g) + 6H2O() D. H2O0) → H2O(g) AH'= -393.5 kJ AH'= -241.8kJ AH'= -2803.0 kJ AH°= +40.7 kJ Why is this change in enthalpy...
Given the following equations and AH' values: C(s) + O2(g) + CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) - H20 (1) AH = -285.8 kJ 2C2H2 (8) + 5O2(g) + 4CO2(g) + 2H20 (1) AH'= -2598 kJ Determine the heat of reaction (in kJ) at 298 K for the reaction: 2C(s) + H2(8) C2H2 (8) 0-136.8 0-219.8 0-109.9 O-167.1 +226.2
Given the following data: () Cu (s) O2 (g)CuO (s) () N2 (g) + 02 (g)NO2 (g) H'--157 kJ AHo+33 kJ calculate AH for the reaction below using Hess' Law. 4 Cu (s) 2 NO2 (g)4 CuO (s) N2 (g)
You are given the following data. AH = = -286.0 kJ H2(g) + 1/2O2(g) → H20(1) N2O5(9) + H20(1) → 2 HNO3(aq) 1/2 N2(9) + 3/2 02(9) + 1/2 H2(9) AH = -77.0 kJ HNO3(1) AH = -174.0 kJ Calculate the AH for the reaction given below. 2 N2(g) + 5 O2(g) → 2 N205(9) k] Need Help? Read It Supporting Materials Periodic Table E Constants & Factors Supplemental Data