Assume all reactants and products are gases unless noted otherwise. Given the following data;
P4(s) + 6Cl2 → 4PCl3 ∆H = -1225.6 kJ
P4(s) + 5O2 → P4O10(s) ∆H = -2967.3 kJ
PCl3 + Cl2 → PCl5 ∆H = -84.2 kJ
PCl3 + 1/2O2 → Cl3PO ∆H = -285.7 kJ
Calculate ∆Hrxn for the following reaction. P4O10 + 6PCl5 → 10Cl3 PO
Assume all reactants and products are gases unless noted otherwise. Given the following data; P4(s) +...
Calculate the value of ΔH° for the following reaction: P4O10(s) + 6PCl5(g) ---> 10Cl3PO(g) P4(s) + 6Cl2(g) ---> 4PCl3(g) ΔH° = -1225.6 kJ P4(s) + 5O2(g) ---> P4O10(s) ΔH° = -2967.3 kJ PCl3(g) + Cl2(g) ---> PCl5(g) ΔH° = -84.2 kJ PCl3(g) + (1/2)O2(g) ---> Cl3PO(g) ΔH° = -285.7 k please explain well i do not understand these kind of problems
32. Given the following data: A. P4(s)+ 6 Cl2(g)4 PCls(g) B. P4(s)+ 5 02(g) P4O10(s)AH=- 2967.3 C. PCls(g)+Cl2(g) PCIS(g) D. PCI3(g)+O2(g) ClaPO(g) AH-285.7 AH 1225.6 kJ AH=-84.2 Calculate AH for the reaction: P4O10(s)+6 PCI5(g) 10 CI3PO(g). Note when I solved this problem, I used 3 of the 4 data reactions, added them together, then used the fourth data reaction to get to the desired reaction. -B-6C+10D+A
3(20 pts) Consider the data: P4(s) + 6 Cl2(g) ----> 4 PC13(g) P4(s) + 5 O2(g) -----> P4010(s) PC13(g) + Cl2(g) ---> PCls(g) PC13(g) + 1/2O2(g) ----> C13PO(g) AH° (kJ/mol) -1226.6 -2967.3 -84.2 -285.7 Using only the above reaction data, compute the AHX of P4010(s) + 6 PCls(8) ----> 10 C13PO (g)
Determine the equilibrium constant, Kgoal, for the reaction 4PCl5(g)⇌P4(s)+10Cl2(g), Kgoal=? by making use of the following information: P4(s)+6Cl2(g)⇌4PCl3(g), K1=2.00×1019 PCl5(g)⇌PCl3(g)+Cl2(g), K2=1.13×10−2
Given the heats of the following reactions: AH° kJ 1. P.(s) + 6C,(g) -->4PCI (g) -1225.6 II. P (s) + 50, (g) ---->P,(s) -2967.3 III. PCI, (g) + Cl, (g) ---> PCI (g) -84.2 IV. PCI,(g) + x0,(g)--->CI PO(g) -285.7 Calculate the value of AH® for the reaction below: P.O.(s) + 6PCI_(8) ---> 10C1, PO(g) -110.5 kJ -610.1 kJ -2682.2 kJ (D) -7555.0 kJ (A) (B)
Use the standard reaction enthalpies given below to determine H°rxn for the following reaction: P4 (g) + 10 Cl2 (g) --> 4 PCl5 (s) ΔHreaction = ? Given: PCl5 (s) --> PCl3 (g) + Cl2 (g) ΔHreaction = +157 kJ P4 (g) + 6 Cl2 (g) --> 4 PCl3 (g) ΔHreaction = -1207 kJ Choices: A. -1835 kJ B. -1364 kJ C. -1050 kJ D. -1786 kJ E. -2100 kJ