Given the heats of the following reactions: AH° kJ 1. P.(s) + 6C,(g) -->4PCI (g) -1225.6...
32. Given the following data: A. P4(s)+ 6 Cl2(g)4 PCls(g) B. P4(s)+ 5 02(g) P4O10(s)AH=- 2967.3 C. PCls(g)+Cl2(g) PCIS(g) D. PCI3(g)+O2(g) ClaPO(g) AH-285.7 AH 1225.6 kJ AH=-84.2 Calculate AH for the reaction: P4O10(s)+6 PCI5(g) 10 CI3PO(g). Note when I solved this problem, I used 3 of the 4 data reactions, added them together, then used the fourth data reaction to get to the desired reaction. -B-6C+10D+A
P,010(s) + 6PC13(g) → 10POCI;(8) 1. The synthesis of phosphoryl chloride (POCI,) is represented in the reaction above. a. Determine the value of the standard enthalpy change AHⓇxn for the synthesis of POCI(g) at 298K using the following information. (5 points) i. P,(s) +6C12(g) → 4PC12(g) AH° = -1225.6 kJ ii. P.(s) + 502(g) →P,0,.() AH = -2967.3 kJ iii. PCI,(g) + Cl, (g) → PC1,(g) AH = -84.2 kJ iv. PCI,(g) + 1/2 0,(g) → POCI,(g) AH° = -285.7...
Assume all reactants and products are gases unless noted otherwise. Given the following data; P4(s) + 6Cl2 → 4PCl3 ∆H = -1225.6 kJ P4(s) + 5O2 → P4O10(s) ∆H = -2967.3 kJ PCl3 + Cl2 → PCl5 ∆H = -84.2 kJ PCl3 + 1/2O2 → Cl3PO ∆H = -285.7 kJ Calculate ∆Hrxn for the following reaction. P4O10 + 6PCl5 → 10Cl3 PO
Calculate the value of ΔH° for the following reaction: P4O10(s) + 6PCl5(g) ---> 10Cl3PO(g) P4(s) + 6Cl2(g) ---> 4PCl3(g) ΔH° = -1225.6 kJ P4(s) + 5O2(g) ---> P4O10(s) ΔH° = -2967.3 kJ PCl3(g) + Cl2(g) ---> PCl5(g) ΔH° = -84.2 kJ PCl3(g) + (1/2)O2(g) ---> Cl3PO(g) ΔH° = -285.7 k please explain well i do not understand these kind of problems
answers ncider 31. The work function for lithium is 279.7 KJ/mol. a. What is the maximum wavelength of light that can remove an electron from an atom on the surface of lithium metal? 5/3 ly 32. Given the following data: A. Pa(s) + 6 Cl:(g)4 PCl(g) B. Pa(s)+ 5 0:(g) P4Oo(s)AH-2967.3 C. PCl(g) + Cl:(g) PCls(g) D. PCIb(g)+%O:(g) ClaPO(g) AH-1225.6 kJ 3ot AH-84.2 AH-285.7 Calculate AH for the reaction: P4O10(s)+6 PCIs(g) 10 ClhPO(g). Note when I solved this problem, I...
- PCI) D ) 10. In cop 0.10-MN 4PCI() AH -1280k 4.ใณใน Assum - 4PCI(s) AH = -1774 kJ calculate 4.184 / & Cakeware for PCHD + C G : PC) - P 10C) *** of water when its The specific heat of 2. Calculate the heat absorbed by 155g of water temperature rises from 18.0°C to 47.5°C. The water is 4.184/8 C Mer is alture rises from sorbed by za & Calculate 4H® for the following reaction: SIO (s)...
3(20 pts) Consider the data: P4(s) + 6 Cl2(g) ----> 4 PC13(g) P4(s) + 5 O2(g) -----> P4010(s) PC13(g) + Cl2(g) ---> PCls(g) PC13(g) + 1/2O2(g) ----> C13PO(g) AH° (kJ/mol) -1226.6 -2967.3 -84.2 -285.7 Using only the above reaction data, compute the AHX of P4010(s) + 6 PCls(8) ----> 10 C13PO (g)
2. Given the following heats of formation, calculate AH for the reaction 2 CO(g) + 5 H2(g) → C2H6 (g) + 2 H2O(g) Compound AH°F (kJ/mol) Compound AH°F (kJ/mol) 52.28 C₂H6 (8) -84.68 C2H4 (8) -393.5 CO2(g) -241.8 H2O(g) -285.9 CO(g) -110.5 H2O(1)
3. For the reaction, P,(s, red) + 10 CL(g) a) AH°(in the units of kcal, kJ, and liter-atm) b) AE (in the units of kJ) c) work (w) (in the units of kJ) 4 PCl,(g), calculate: АН, Р =-73.6 kJ mol 4(s,red) AHP PCI,(g) = -398.9 kJ mol 6. For a chemical process 50. kJ of heat energy were released and 20. kJ of work were done by the system. Calculate AE for this process.
Need Help 2. Given: Pa(s) + 3 O2(g) → P.O(s) AH = -1640.1 kJ Pa(s) + 5 O2(g) → P4010(s) AH = -2940.1 kJ Use Hess Law to calculate the AH for P.O(s) + 2O2(g)→ P4010(s)