Calculate the Kb of the conjugate base of a weak acid with a Ka = 5.28...
Calculate the Kb of the conjugate base of a weak acid
with a Ka = 5.28 × 10−5.
- report answer in three significant
figures
- answer should be written in scientific
notation
(ex. 4.67E-7 or 4.67E7 be sure to
use a CAPITAL E not lower case 'e')
Homework Answers
![with Ka = 5.28x10-5 1.0x10-14 [ Ka ] 1.0x10-14 [ 5.28x10-5 Kb = 1.89x10-10 Kb = 1.89E-10 Kb =](http://img.homeworklib.com/questions/6e6b3c60-d851-11eb-8cc7-7b0664ca70c8.png?x-oss-process=image/resize,w_560)
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Calculate the Kb of the conjugate base of a weak acid
with a Ka = 5.28...
1a. A weak monoprotic base has a Kb = 1.67 × 10−10. Calculate the Ka for...
1a. A weak monoprotic base has a Kb = 1.67 × 10−10. Calculate the Ka for the conjugate acid of this base. Report your answer to THREE significant figures. You may (but are not required to) enter your answer in scientific notation; for example, if your answer is 2.44 × 10-2, you would enter 2.44E-2. The E must be uppercase. 1b. A weak monoprotic base has a Kb = 3.38 × 10−3. Calculate the Ka for the conjugate acid of...
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part 1 A weak monoprotic base has a Kb = 2.43 × 10−10. Calculate the Ka for the conjugate acid of this base. Report your answer to THREE significant figures. You may (but are not required to) enter your answer in scientific notation; for example, if your answer is 2.44 × 10-2, you would enter 2.44E-2. The E must be uppercase. part 2 A weak monoprotic base has a Kb = 3.71 × 10−9. Calculate the Ka for the conjugate...
A .175 M weak acid solution has a pH of 3.25. Calculate the Ka for the...
A .175 M weak acid solution has a pH of 3.25. Calculate the Ka for the acid. (hint your answer should contain three significant figures and be written in scientific notation ex. 4.67E-2 )
A weak base has Kb = . Calculate the hydrolysis constant, Ka, for the weak conjugate...
A weak base has Kb =
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Question 39 1 pts A weak acid (HA) reacts with a weak base (B) to form the conjugate base of the acid (A) and the conjugate acid of the base (B-H the pKa of HA was 4.8 and the pKa of BH* (i.e., the p...
Question 39 1 pts A weak acid (HA) reacts with a weak base (B) to form the conjugate base of the acid (A) and the conjugate acid of the base (B-H the pKa of HA was 4.8 and the pKa of BH* (i.e., the pKabH of B) was 9.4, what would be the value of the equilibrium constant for the above reaction to the nearest ones? Obviously, by expressing the answer to the nearest ones, we are using too many...
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C5H5N (ethylamine) is a weak base. Kb=1.7x10-9. Write an acid dissociation reaction for its conjugate acid....
C5H5N (ethylamine) is a weak base. Kb=1.7x10-9. Write an acid dissociation reaction for its conjugate acid. Then, calculate its Ka.
A weak acid (HA) reacts with a weak base (B) to form the conjugate base of...
A weak acid (HA) reacts with a weak base (B) to form the conjugate base of the acid (A-) and the conjugate acid of the base (B-H+). If the pKa of HA was 4.7 and the pKa of BH+ (i.e., the pKabH of B) was 9.4, what would be the value of the equilibrium constant for the above reaction to the nearest ones? Obviously, by expressing the answer to the nearest ones, we are using too many figures than is...
Be sure to answer all parts. Be sure to report your answer to the correct number...
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