Question

Determine the amount of heat, in kJ, that is released when 2.481x10 mg Pt203 decomposes according the reaction shown below? n

pls confirm if i balanced the chem equation correctly
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Answer #1

3 clance equation AH = -943.2 kJ 2 Pt203 mor of Pt₂ oz = 302 + 4 pt man = 2.481x1029 [img=1039] MW 438.115 g/mol 0.5 6 8 mol

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