As it is salt
pH = 1/2(14+pKa2 + logC)
8.82=1/2(14+pKa2 + log(0.2))
pKa2 = 4.34
Ka2 =4.57×10-5
8. If the pH of a 0.20 M potassium oxalate solution is 8.82, calculate the experimental...
(8) Is the pH or a 0.20 M potassium oxalate solution is 8.82 calalate the experimental value for Kaz for oxalic acid
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