Question

Complete The Following Flow Chart. Nonelectrolyte Element Pure Substance Solvent Compou

If the solubility of KCl in 100 mL of H2O is 34 g at 20°C and 43 g at 50°C, label each of the following solutions as unsaturated, saturated, or supersaturated. If more solid is added than can dissolve in the solvent, assume that undissolved solid remains at the bottom of the flask. a. adding 35 g to 100 mL of H20 at 20°C: (select) b. adding 41 g to 100 mL of H20 at 50°C: (select) c. adding 13 g to 30 mL of H20 at 20°C: (select) d. adding 39 g to 100 mL of H,0 at 50°C and slowly cooling to 20°C to give a clear solution with no precipitate: (select) < Prev 3 or 12 m Next >

Answer 1

- Given :. Solubility of ku in 100 ml of H₂O a lut 20°c ' 34 gm /per 100ml at 50°c = 43 gm I per loo one (a) .35g of ka is added at 20°C but solubility ef Kaislanty 349m loomi so, solution is super saturated (6) solubility is 43 gm/soome at 50c but, so agm. more ka can be added so solution is unsaturated () at zo'c = 349m in loome so solubility in some = 17 gm and 13 gm is added so unsatwated. (d) Initially solution will be unsaturated at sooc but later it was cooled to 20°C slowly and the solubility of ky at 2oc in 34gm kell loome only 39_solution will become superzsaturated