Question

C) semiconductor D) nonconductor strong electrolyte 10. When some of the sugar added to iced tea remains undissolved at the bottom of the glass, the solution is A) dilute B) polar C) nonpolar D) saturated unsaturated 11. The solubility of KI is 50 g in 100 g of H20 at 20 °C. If 110 grams of KI are added to 200 gram H20,- A) all of the KI will dissolve B) the solution will freeze C) the solution will start boiling D) a saturated solution will form E) the solution will be unsaturated

Answer 1

When some of the sugar is added to tea remains undissolved at the bottom of the glass then the solution is saturated solution because in saturated solution No more solute can dissolve in the solvent at given temperature. so, option is D. Given that 50 g of KI soluble in 100 g of H_2 at 20 degree c from this only 100 g of KI will only soluble in 200 g and 10 g of KI will remain because the solution is saturated with 100 g of KI option is D.

Answer 2

correct options are:

1. d

2. d