Formic acid (HCOOH) has a pka = 3.75. What is the value of the equilibrium constant...

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Answer 1

Answer #1

pka is given for HCOOH.

but reaction is given for base ie HCOO-

hence, to find pkb then kb. and kb is the equilibrium constant.

Soln pki for noon = 3.78 - play for tod=44-3-75310.26 ki = 10-pkb *6 = 10-10-25 K2=15-62 *10-, opta (() is correct.

Answer 2

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