Question

U Resources Give Up? Hint Check Answ B of 33 > Calculate either H,0") or (OH" for each of the solutions. Solution A: (OH) = 1.23 x 10-7M Solution A: [H,0+) = Solution B: H, 0+) = 7.79 x 10-M Solution B: [OH") = Solution C: H0+) = 6.15 x 10-M Solution C(OH") = Which of these solutions are basic at 25°C? A: OH") = 1.23 x 10-'M B: H,0") = 7.79 x 10°M C:H,01 -6.15 x 10 - M MacBook Air

Answer 1

Dear student,

As we know that the expression for conization constant g water kw is given as Kw = [Hot] [oH] = 1014 - ci Now, solation A :-[OH-] = 1.23x10 AM putting in eqn cis, we get & 10th = [Hgot] x 1,23x10-7 & [H3O+] = 0.813 x 10 77 M. 8.13 x 10-8 M Solution Br [H3O+] = 7.79810-9 putting in equ (1), we get y 10-14 = 7.49 * 10 9 x [OH-Y & [or] =0.128 x 10-5m = 1.28 x 10-6M

Solution Ci- [M30t] = 6.15 x 10-4M putting in eqn is, we get 1044 = [H 30 t] x 6.15 x 10-4 & [H3O+] = 0.163 x 10-10 m 17 = 1.63 X 10-11

2 The solution whose ph is greater than f is known as basic solution and the pH expression is ginen as pH = -log [ht] - i A Cor ] =1-23 x 10-7M poH = -log [or =- log (1.23 x 10-7) = 6.91 Now, pH = 14-POH = 14 -6.91 = 7.09 since, pH is very close to 7. so, we can assume it to be neutral Bir [H₂ot] = 7.79x10-9 pH = -log [M90t] = - log (7.79 x 1009) = 8.12 Since, pH is greater than 7, therefore et és basic solution.

Ci [Hgot] = 6.15*10-4M pH = -log [H2o+] = - 109 (6:15 x 10-4) = B.21 Since, pH is less than 7, therefore it is acidic solution.

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