Question

5/5 Which of these neutralization reactions has a pH >7 when equal molar amounts of acid and base are mixed? A) HC2H:02 (aq) + LiOH(aq) = H2O(l) + LiC,H,O, (aq) B) HI(aq) + NH3(aq) = NHI (aq) C) HI (aq) + KOH(aq) = H2O(l) + Kl(aq) D) HCl (aq) + NH3(aq) = NHACI (aq) . Which of these neutralization reactions has a pH <7 when equal molar amounts of acid and base are mixed? A) HC H302 (aq) + LiOH(aq) = H2O(l) + LiCH02 (aq) B) Hl(aq) + NH3(aq) = NHI (aq) C) HI (aq) + KOH(aq) =H2O(1) + Kl(aq) D) HNO2(aq) + KOH (aq)=KNO2(aq) + H20() 3. What volume of 5.00 x 10' M HNO3 is needed to titrate 45.00 mL of 3.00 x 102 M NaOH to the equivalence point? A) 45.0 mL B) 90.0 mL C) 135 mL D) 270 mL

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Answer 1

A neutralization reaction between an acid & a . bare produce salt and walu (Hence, salt solution) The pH of salt solution depends upon its acidic or basic nature for an Acidic salt solution * pH is less than 7. for an Basic salt solution ph is more than 7. for neutral salt solution » pH is = 7. - pH of salt solution . . To predict the salt type first consider the dissociati- -on g salt into ils consitutent anion & cation. then check the nature of cations / anions as neutral, acidic or basic . ay HC₂ H₂O₂ (aq) + 46 04 (aq.) 2 H₂O (1) + LICH, 0o (og. valt Dissociation of salt Li Chycoo (0%) — Li + Che coo since CH₂600 is anion of a weak acid (CH₂ 2001), it is مه b . And Lit is cation of a strong base (Lion), it is neutral. so the overall salt solution would be basic because 9 CMy coo" 1. Chcoo- + H-OH ² CH₃COOH + on (responsible Hence pH of for basicily the above neutralization reaction is greater than 7. by HI @q;) + NH3 (aq;) = NHU I (aq.) 1. salt) NM* I = NHYT + I- - NHIt is an acidic cation ( since it is a cation of - weak base NH4OH) I is neutral (as, it is anion of strong acid HI) So NMy I solution would be lacidic Hence pH will be <7. cy HI (Op.) + KOM (29.) = H2O Hy + KI(a9') Kt is neutral (as, it is cation of strong base KOH) I is neutral (as, it is anion of strong acid & HI) & KI + k + I neutral neutral SO, KI solution will be neutral Hence, pH=7 dy He + NH3 = Nou all ap.) (HU) . Nhace - Nhyt te - Nhyt is an acidic cation ( since it is a cation of weak hare NH4OH) - ce is neutral because it is anion a strong acid . Nhyce - Nhut té (acidic) (neutral) N447 + H20 - Nhyon + H+ (responsible for acidic salt solution) So Nnya will be laudic solution | IPH <1) + HNO, (09-) + KOH Copos = KNO2 (as) + H2011) KNO, → kt + NO, : Kt is neutial & No is basic (as it is anion Of weak acid HNO2) NO + H20 - HNO2 + ou- 1. (responsible for basic walt salation). Hence KNO₂ solution would be of basic sall solution & pH will be greater than 7. 98 - Titiation The reaction involved is HNO3 (09.1+ NaOH (ap- Na NO, (aq) + 42010) Mi (molarity of HNO3) = 5x10-3M V, ( volume HNO3) = ? (ML) My ( molority of Noon) = 3x 10-2M ♡ ( volume 9 Naon) = 45.00 ML At equivalence point 1. No. of moles of acid = no. g moles of base since no.9 moles - molority x volume → at equivalence point T MY, M 2 (Acid) (base * v = M₂ V2 = 3x102 M x 45 mL - 5 x 10-3 M y = 27 x 10 mL lv,= 270 mL Ary