Question

Enter your answer in the provided box. Calculate the molality of the following aqueous solution: 0.670 M KOH solution (density of solution = 1.04 g/mL)

Answer 1

ماجرا 0.67 M KOH solution density = 1.04 g/me To find- Motality (m) 0.67M solution means 0 67 moles of KoH dissolved in Il cs 10vo ml of solution no, of moles = dissolved mass Molar mass of kol 0.67 mol = Mass of solute dissolved - 39+16+1 g/mol 0.67X56 = Mass of dissolved kon Mass of solute dissolved is = 37.52 we know Density - Mass - Volume 1004 g/ me = Mass of falutisan - Volumě Jesolution = lovome. I Mass of solution - 1040 g $canned with SamScanner

Mass of solvent = Mass of solution - Mass of solute = 1040 g - 37.52 g = 1002 Y8g no. of moles of solute dissolved Mass of linkg) solvent Now Molality = O. 67 molx 1000 1002,48 1670 0.668 mdfkg 100248 ed with scanner