Enter your answer in the box provided. What is the molality of a solution consisting of 31.9 mL of benzene (C6H6; d = 0.877 g/mL) in 343 mL of hexane (C6H14; d = 0.660 g/mL)
moality = mol solute / kg solvent
MW benzene= 78.11 G7mol
mol solute= mass/MW = D*V/MW = (31.9*0.877)/(78.11 ) = 0.358165 mol of S
kg solvnet = DV = 343*0.66/1000 = 0.22638 kg
then
molality = 0.358165/0.22638 = 1.58214molal
Enter your answer in the box provided. What is the molality of a solution consisting of...
a. Calculate the mass of iodine, I2, that must be dissolved in 725 mL of carbon disulfide, CS2(d= 1.261 g/mL) to produce a 0.236 msolution. b. Calculate the molality of a solution consisting of 34.0 mL of benzene (C6H6, 78.11 g/mol, d= 0.877 g/mL) in 187 mL of hexane (C6H14, 86.18 g/mol, d= 0.660 g/mL).
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