Determine the structure using NMR. CH120 2.6 1.0 PPM Ράς ΝΜ 3. integral values 100 10...

Question

Question

Determine the structure using NMR.
CH120 2.6 1.0 PPM Ράς ΝΜ 3. integral values 100 10 PPM 0 1 NMR

Answer 1

Answer #1

9 - TLC © Double bond equivalent of C514120 = 571-12 conclusion: Only single bond PA presenten @ Five different types of prot

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Answer 2

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