Given the following two half reactions, Cd(aq) + 2e → Cd(s) E° = -0.40 V 2...
Given the following two half reactions, Cd
(aq)
+ 2e
→ Cd(s) E° = -0.40 V 2 Ag
(aq)
+ 2e
→ 2 Ag(s) E° = 0.80 V determine E° and the spontaneity of the
following reaction: 2 Ag(aq)
+ Cd(s) → 2 Ag(s) + Cd(aq)
Homework Answers
So
the required E0 is 1.2V . 
Add Answer to:
Given the following two half reactions, Cd(aq)
+ 2e
→ Cd(s) E° = -0.40 V 2...
Consider the following half-reactions: Half-reaction E° (V) Ag+(aq) +e → Ag(s) 0.799V Cu2+(aq) + 2e →...
Consider the following half-reactions: Half-reaction E° (V) Ag+(aq) +e → Ag(s) 0.799V Cu2+(aq) + 2e → Cu(s) 0.337V Mg2+(aq) + 2e —— Mg(s) -2.370V The strongest oxidizing agent is: enter symbol The weakest oxidizing agent is: The weakest reducing agent is: The strongest reducing agent is: Will Mg(s) oxidize Ag(s) to Ag+(aq)? V Which species can be oxidized by Cu2+(aq)? If none enter none. Consider the following half-reactions: Half-reaction E° (V) 2Br (aq) 1.080V Br2(1) + 2e — Ni2+(aq) +...
Given the two following half reactions, Cr(aq) + 3e- → Cr(s) E° = -0.74 V Hg2(aq)...
Given the two following half reactions, Cr(aq)
+ 3e- → Cr(s) E° = -0.74 V Hg2(aq)
+ 2e- → Hg(l) E° = +0.80 V calculate the standard emf for the
following cell: Cr | Cr||
Hg2|
Hg
Consider the following half-reactions: Half-reaction E° (V) Hg2+(aq) + 2e- ----> Hg(l) 0.855V Cd2+(aq) + 2e-...
Consider the following half-reactions: Half-reaction E° (V) Hg2+(aq) + 2e- ----> Hg(l) 0.855V Cd2+(aq) + 2e- --->Cd(s) -0.403V Mg2+(aq) + 2e- --->Mg(s) -2.370V (1) The strongest oxidizing agent is: enter formula (2) The weakest oxidizing agent is: (3) The weakest reducing agent is: (4) The strongest reducing agent is: (5) Will Mg2+(aq) oxidize Hg(l) to Hg2+(aq)? _____yes/no (6) Which species can be reduced by Cd(s)? If none, leave box blank.
Classify the half‑reactions as reduction half‑reactions or oxidation half‑reactions. H2(g)⟶2H+(aq)+2e−H2(g)⟶2H+(aq)+2e− 12O2(g)+2H+(aq)+2e−⟶H2O(g)12O2(g)+2H+(aq)+2e−⟶H2O(g) Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e−Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e− 2NiO(OH)(s)+2H2O(l)+2e
Classify the half‑reactions as reduction half‑reactions or oxidation half‑reactions. H2(g)⟶2H+(aq)+2e−H2(g)⟶2H+(aq)+2e− 12O2(g)+2H+(aq)+2e−⟶H2O(g)12O2(g)+2H+(aq)+2e−⟶H2O(g) Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e−Cd(s)+2OH−(aq)⟶Cd(OH)2(s)+2e− 2NiO(OH)(s)+2H2O(l)+2e−⟶2Ni(OH)2(s)+2OH−(aq)2NiO(OH)(s)+2H2O(l)+2e−⟶2Ni(OH)2(s)+2OH−(aq) Fe(s)⟶Fe2+(aq)+2e−Fe(s)⟶Fe2+(aq)+2e− oxidation reduction reduction oxidation reduction
Question 9 of 33 Consider the following half-reactions: 12(s) + 2e → 2 (aq), E°(red) =...
Question 9 of 33 Consider the following half-reactions: 12(s) + 2e → 2 (aq), E°(red) = 0.54 V, Cd2(aq) + 2 e → Cd(s), E° (red) = -0.40 V. Will the electrochemical cell represented by | 12 || Cd2+ | Cd be galvanic or electrolytic under standard conditions? A) Galvanic B) Electrolytic C) Not enough information to search o i ne 9 101 A W 70% ^ a
Given are two half-cells, described by the equations: Zn^(2+)(aq) + 2e- -> Zn(s) E(standard) = -0.76 V Ag^(+)(aq) + e...
Given are two half-cells, described by the equations: Zn^(2+)(aq) + 2e- -> Zn(s) E(standard) = -0.76 V Ag^(+)(aq) + e- -> Ag(s) E(standard) = +0.80 V A. Write down the net equation for the spontaneous reaction that takes place in the cell. B. Draw the two half cells and mark the anode and the cathode. C. Mark the solutions' concentration necessary in order to reach the standard potential. D. How will the cell's potential be influenced by the addition of...
A voltaic cell is based on the following two half-reactions: Cd2 (ag) +2e-> Cd (s) Sn2(aq)+...
A voltaic cell is based on the following two half-reactions: Cd2 (ag) +2e-> Cd (s) Sn2(aq)+ 2e Sn (s) Calculate the standard cell potential. Use the date from the attached table.SRP2.docx Oa 0.13 Ob 042 Oc.027 Od-0.27
Half-Reaction Fe2+(aq) + 2e Fe(s) Hg2+ (aq) + 2e Hg() Ag+ (aq) + e + Ag(s)...
Half-Reaction Fe2+(aq) + 2e Fe(s) Hg2+ (aq) + 2e Hg() Ag+ (aq) + e + Ag(s) Cu2+ (aq) + 2e + Cu(s) Zn2+ (aq) + 2e → Zn(s) E (V) -0.44 0.86 0.80 0.34 - 0.76 Using the table, calculate Eºcell for the following electrochemical cell under standard conditions voltmeter a) 1.24 V Fe. salt bridge Ag b) -1.24 V c) 2.04 V d) - 2.04 V Ag a b С
Consider the following half-reactions: Half-reaction E° (V) 12(s) + 2e - →21(aq) 0.535V Ca2+ (aq) +...
Consider the following half-reactions: Half-reaction E° (V) 12(s) + 2e - →21(aq) 0.535V Ca2+ (aq) + 2e → Cd(s) -0.403V All(aq) + 3e -Al(s) -1.660V (1) The weakest oxidizing agent is: enter formula (2) The strongest reducing agent is: (3) The strongest oxidizing agent is: (4) The weakest reducing agent is: (5) Will Al(s) reduce 12(s) to l'(aq)? (6) Which species can be reduced by Cd(s)? If none, leave box blank. Submit Answer Retry Entire Group 9 more group attempts...
1)Consider the following half-reactions: Half-reaction E° (V) Cl2(g) + 2e- > 2Cl-(aq) 1.360V Cd2+(aq) + 2e-...
1)Consider the following half-reactions: Half-reaction E° (V) Cl2(g) + 2e- > 2Cl-(aq) 1.360V Cd2+(aq) + 2e- > Cd(s) -0.403V Al3+(aq) + 3e- > Al(s) -1.660 The strongest oxidizing agent is: _______ enter formula The weakest oxidizing agent is: _______ The weakest reducing agent is: _______ The strongest reducing agent is: _______ Will Al3+(aq) reduce Cl2(g) to Cl-(aq)? _____yes or no Which species can be reduced by Cd(s)? If none, leave box blank. 2) Use the table 'Standard Reduction Potentials' located...
Consider the following half-reactions: Half-reaction E° (V) Ag+(aq) +e → Ag(s) 0.799V Cu2+(aq) + 2e → Cu(s) 0.337V Mg2+(aq) + 2e —— Mg(s) -2.370V The strongest oxidizing agent is: enter symbol The weakest oxidizing agent is: The weakest reducing agent is: The strongest reducing agent is: Will Mg(s) oxidize Ag(s) to Ag+(aq)? V Which species can be oxidized by Cu2+(aq)? If none enter none. Consider the following half-reactions: Half-reaction E° (V) 2Br (aq) 1.080V Br2(1) + 2e — Ni2+(aq) +...
Given the two following half reactions, Cr(aq)
+ 3e- → Cr(s) E° = -0.74 V Hg2(aq)
+ 2e- → Hg(l) E° = +0.80 V calculate the standard emf for the
following cell: Cr | Cr||
Hg2|
Hg
Question 9 of 33 Consider the following half-reactions: 12(s) + 2e → 2 (aq), E°(red) = 0.54 V, Cd2(aq) + 2 e → Cd(s), E° (red) = -0.40 V. Will the electrochemical cell represented by | 12 || Cd2+ | Cd be galvanic or electrolytic under standard conditions? A) Galvanic B) Electrolytic C) Not enough information to search o i ne 9 101 A W 70% ^ a
A voltaic cell is based on the following two half-reactions: Cd2 (ag) +2e-> Cd (s) Sn2(aq)+ 2e Sn (s) Calculate the standard cell potential. Use the date from the attached table.SRP2.docx Oa 0.13 Ob 042 Oc.027 Od-0.27
Half-Reaction Fe2+(aq) + 2e Fe(s) Hg2+ (aq) + 2e Hg() Ag+ (aq) + e + Ag(s) Cu2+ (aq) + 2e + Cu(s) Zn2+ (aq) + 2e → Zn(s) E (V) -0.44 0.86 0.80 0.34 - 0.76 Using the table, calculate Eºcell for the following electrochemical cell under standard conditions voltmeter a) 1.24 V Fe. salt bridge Ag b) -1.24 V c) 2.04 V d) - 2.04 V Ag a b С
Consider the following half-reactions: Half-reaction E° (V) 12(s) + 2e - →21(aq) 0.535V Ca2+ (aq) + 2e → Cd(s) -0.403V All(aq) + 3e -Al(s) -1.660V (1) The weakest oxidizing agent is: enter formula (2) The strongest reducing agent is: (3) The strongest oxidizing agent is: (4) The weakest reducing agent is: (5) Will Al(s) reduce 12(s) to l'(aq)? (6) Which species can be reduced by Cd(s)? If none, leave box blank. Submit Answer Retry Entire Group 9 more group attempts...
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