Question

At a certain temperature the vapor pressure of pure benzene (CH) is measured to be 121. mmHg. Suppose a solution is prepared by mixing 80.9 g of benzene and 64.6 g of thiophene (C4H4S). Calculate the partial pressure of benzene vapor above this solution. Be sure your answer has the correct number of significant digits. Note for advanced students: you may assume the solution is ideal. í mmHg x 5 ?

Answer 1

10 Umu The given problem will be solved by using the formula Po - PS - Xalute where po = vapom pressine o fere Leuzene = 121mm ng - Ps= vapom pressure of solution = ? Xsolute = more fruction of salute = nsolute Noolule tu solvent nastule = 64.68 e a almal 0.77mul n solvent =8 12 = 1.04 mol 8mg, Xsolute = 0.75 mol = 0.77 mol 0.77 mol +1.04 mol 1.8lmer = 0.4254 121 mm Hg - ps = 0.4254 12 mm Hg 121 mmHq - ps = 51.47 mm Hg Ps = 121mm Hg - 51.47 mm Hg Ps = 69.53mmHq