According to Dalton's law of partial pressures
Ptotal= P1+P2+P3 ..............................(1) or
Ptotal= R [n1T1/ V1 + n2T2/ V2 + n3T3/ V3 ]
From this we can calculate Ptotal from eqn (1)
Ptotal= 399+600.1+405
= 1404.1 torr
Also ,we know the partial pressure of the individual gas is found out by
P1= Ptotal x Xi where Xi is the mole fraction
Let us denote urea=1 ,NO=2, O2=3
So
X1 =n1 / n1+n2 +n3 [ from the above eqn n1=2,n2=4,n3=1 ]
= 2/7= 0.285 moles
Similarly, X2= 4/7=0.571moles
X3= 1/7 = 0.142 moles
Partial pressure of individual components
1.urea
P1=1404.1 X0.285 =1114.5 torr
2. NO
P2=1404.1X 0.571=801.7 torr
3. O2
P3= 1404.1 X 0.142= 199.3torr
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