1) Given:
Heat of Vaporization of freon = 38.6 cal/gm
Mass of freon = 1.30 kg = 1.30× 1000 = 1300 GM
Since, 1gm freon removes 38.6 cal heat
So, 1300 gm freon will remove
=38.6×1300= 50180 cal heat (Answer)
References Liquid freon (CC12F2) is used as a refrigerant. It is circulated inside the cooling coils...