Question

12 Instructions Question 1 10 pts A 3.00 L sample of argon (Ar) has a pressure of 345 kPa at 55.0°C. What volume would the sample have if the pressure is 0.839 atm and the temperature exactly 0°C? 0.6141 60.5L 22.4L 10301 10.12

Answer 1

by ideal gas equation we know that

PV=nRT

So here the factor n is constant and R is universal gas constant

it can be equated as

PV EV, Ti Т)

Given

P1=345 kPa

P2=0.839 atm=0-839*101.325= 85.011675 KPa

V1=3 L

T1=55 + 273 =328 K

T2=273K

substituting in eqn we get

85.011675 *V2 273 345 * 3 328

V = 10.133292

so the answer is 10.1 L