Question

1. The diazenide ion, N22-, is a recently isolated compound, discovered to ionically bind to alkaline earth metals. a. Draw an MO diagram for N22-. Your diagram should include symmetry labels for all atomic and molecular orbitals, as well as their relative energies. b. Determine the bond order of N22- c. Is N22-a diamagnetic or paramagnetic compound? d. In contrast with N2-, the analogous carbon and oxygen based ions, peroxide (022) and acetylide (C2have been known to exist for a long time. The bond distances for these complexes are given below: Compound Bond Distance (pm) 119 149 0,2- Through comparison of their electronic structures, provide an approximation for what you might expect to be the bond distance for N22

Answer 1

The MO diagram for the N2-- is below in the hand written notes.

And the answers for the part A,B,C and D are also in the hand written notes.

@ The mo diagram for diazenide ion (NG) : (282) 11 (3) *UR) (284) (3) TV Energy GP2) (9) TV 11 (M) (280 (spy) Cars t th (m) 1K EnEXM THE ها ( كی There are the in agh and we fill them the Mo diagram of W₂ - according gt gerade = Symmetric ungerade & Antigymmetric M

. The formula for bond order ist B.O. = nb. ofé in Bonding orbitals - No de în Anh Bonding O.. from the mo of ng 2 - - B.O. = 10 + 6 a 9 = 2 Bond order of W₂ 2 = 2 - - As seen from the mo of N₂ ²- it has 2 unpaired electrons so, Ny² is a paramagnetic compound. d Compound (w Bond distance (Pm) 119 8 If we et w calculate B. o. of ( 2 = 1 B.o. of or 2 B.o. of N, 2 = know that o and we

Bond order a Bond strength a - Bond length As the bond order 02- and less than of N 62 = 2 Bond kes is order, more than so - The the then Bond length of N2- must be less than Bond length of o2- and must be greator the Bond length of Bond length of N₂ 2- lies between 129 pm and 149 pm