According to Henderson-Hasselbalch equation
pH = pKa +log ([Base]/[Acid])
pKa = -logKa = -log(1.38 x 10-4) = 4- log(1.38) = 4 - 0.1398 = 3.860
pH = 3.86 + log (0.65/0.62) = 3.86 + log (1.048) = 3.86 + 0.02 = 3.88
pH = 3.88
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QUESTION 3 What is the pH of a buffer solution composed of HA and A (Ka...
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