If 3.50 KJ of energy is absorbed by a metal sample that has a mass of...
If 3.50 KJ of energy is absorbed by a metal sample that has a mass of 118.0 grams, and the temperature increased from 25.0oC to 255oC, what metal could the sample be?
Homework Answers
Heat absorbed by the metal(q) is calculated by the following formula
q = m × ∆T × Cs
m = mass of the metal, 118.0g
∆T = Temperature difference , 255℃ - 25.0℃ = 230℃
Cs = specific heat capacity of the metal
Cs = q/(m × ∆T)
= 3500J/(118.0g × 230℃ )
= 0.129 J/g℃
specific heat capacity of gold is 0.129J/g℃
Therefore,
The metal could be gold
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