Question

0.04M 0.1M Initial I Concentration Initial S2082- Concentration Show a calculation of how you calculated the rate of reaction Rate of Reaction Use M/s to represent (mol/L)/s Show a calculation of how you calculated the relative rate of reaction Relative Rate of Reaction

How do I calculate the Rate of Reaction and the Relative Rate of Reaction?

Answer 1

Answer:

The reaction is:

S​​​​​​​​​2O8​​​2- (aq) + 2I-(aq) $\rightarrow$ 2SO42-(aq)+I2(aq)

So we know that rate of reaction is change in concentration of reactants per unit time

Or rate = -∆[S2O8​​​2- ]/∆t. mol/lit-s ..........(1)

Here ∆t = 94 s

Change in number of moles(consumption) of S2O82- is given in the experiment as 2.5*10^-5 moles

Total volume of the solution = 50 ml = 0.05 lit

Or ∆[S2O8^ 2-] = - 2.5*10^-5/0.05 ( negative because conc. Is decreasing)

=-0.0005 mol/lit

Or rate = -∆[S2O8^2-]/∆t = -(-0.0005)/94

= 5.319* 10-6 mol/lit.sec

Relative Rate of reaction:

You can calculate rate of reaction as per equation (1) above for the no.of trials you have performed.Assign each rate a symbol as Rate1, Rate2 etc.

Now find out the smallest value of theses rates say Rate2

Not find the relative rate for each trial just divide the rate of the trial by this smallest value.

So , Relative Rate for first Trial = Rate1/Rate 2 ( will be > 1)

Relative rate for second trial = Rate2/Rate2 = 1