Question

II. Rate Measurement - Solution 2 1. Calculate the rate of reaction for the solution to turn from colorless to blue-black aft
Solution 1: K+0.6961? morzs Solution 2: K=0.7 (? mol-25- Solution 3: K=0.88 L? molls-
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Answer #1

1) Reaction steps :

The iodide ion (I-) and persulfate ion (S2O82-) reacts to produce I2 (Iodine) and sulfate (SO42-) .

Ammonium persulfate oxidises iodide to iodine.

  S2O82- + 2 I- --> 2 SO42- +  I2

The Iodine formed is immediately consumed by thiosulfate ion  (S2O32- )

Sodium thiosulfate is used to reduce iodine to iodide

2 S2O32-   +  I2 -->   S4O62- + 2  I-

As all  S2O32 are consumed , the excess of iodine will react with starch to form blue colour solution.

  I2 + (C6H10O5)n .H2O --> blue complex

Rate of the reaction =     Volume of (S203)2-(L) XConcentration of (S203)2-moll 2 xVolume of solution (L) Xtime (s)

here volume of the S2O32-    as well as volume of solution and time is given, But the concenration of S2O32-   is unkown.......to find the rate of the reaction.

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