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What is the concentration of Cu2+ (aq) in a solution that was originally 0.015 M Cu(NO3)2 and 0.1M NH? The Cu2+ ion forms the
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Answer [ 24 ] = 0.015H [Why] = 0.1m The Complex in [Cu (NH3)4] ferres in solusion wir 4 - 4,981012 Cu 2 + 4 NH3 - Cu(NH3), 27h) ج وہ ہا + م OM 0.015 - px 0.04 0.1-460.015) +420. 3.0.04. as xis very small x 0.015 kd= [c4 24] [Nuagh لی مین C kartet 2x6I hope this helps you understand the solution and concept. Please rate this answer :)

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