Concentration of OH- = 4.20 x10^-5M
[OH-] = 4.20 x10^-5M
Negative logaritam of Hydroxide ion concentration is called as POH
POH = -log[OH-]
POH = - log(4.20 x10^-5)
POH = - [ log(4.20) + (-5) log 10]
POH = - [ 0.623 + (-5) (1)]
POH = 4.38
But, PH + POH = 14
PH = 14 - POH
PH = 14 - 4.38
PH = 9.62
QUESTIONS Calculate the pH of a solution that has a[OH) = 4.20 x 10-SM (significant figures)...
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Calculate:
Part A) [H+] for [OH−]=3.5×10^-4 M Express your
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Part B) [H+] for [OH−] =8.4×10^-9 M Express
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Part C) Calculate [H+] for a solution in which [OH−] is 100
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Please show how you solved it, thanks!
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