why is an additional 3.00 mL of NaOH added to the reaction solution, beyond what is required for neutralization?
A. |
To ensure that HCl is present in excess. |
|
B. |
To increase the temperature change that results from the reaction. |
|
C. |
To decrease the temperature change that results from the reaction. |
|
D. |
To ensure that NaOH is present in excess. |
Question: why is an additional 3.00 mL of NaOH added to the reaction solution, beyond what is required for neutralization?
ANswer: D. To ensure that NaOH is present in excess.
Titration requires small amount of excess of hydroxide ions (OH−) in solution. which react with indicator (phenolphthalein molecules) and changing it from the acidic form to the basic form.
why is an additional 3.00 mL of NaOH added to the reaction solution, beyond what is...
50
ml HCL solution was added to 51 ml NaOH
1. Would the following errors result in a higher or lower heat of neutralization? a. Student transferred 40,0 mL of HCI instead of 50.0 mL H b. Student used the temperature at 15 min. as final temperature instead of using the graph. Student used the specific heat of water, 4.184 J/g°C instead of the specific heat of C. the NaCl solution, 3.98 J/g°C. If the theoretical heat of neutralization for...
An aqueous solution of HCl is added to an aqueous solution of NaOH in a coffee cup calorimeter. The reaction is that of neutralization between the acid and the base: HCl + NaOH LaTeX: \rightarrow→ H2O + NaCl To calculate the approximate enthalpy change for this reaction using q = mLaTeX: \cdot⋅CLaTeX: \cdot⋅LaTeX: \DeltaΔT, what value should the student give to C in the equation ?
3. 50.0 mL of 1.00M NaOH was added to 50.0mL of 1.00M HCl in a coffee-cup calorimeter. The temperature of the water increased from 25.0°C to 31.5°C. (A)How much heat in Joules was produced by the reaction? (B) What is the AH for the neutralization of 1.00 mol of HCI?
A volume of water was heated to 82.86C and immediately added to 50.31 mL of water at 22:45 °C contained within a coffee cup calorimeter. The final temperature of the mixture was 37,08°C. The final volume of water inside the calorimeter was 94.33 mL. Calculate the following: Note: Heat capacity a. volume of hot water added is 4.18 *Consider sig fig b. masses of hot and cold water (density of water = 1,00 g/mL) c. changes in temperature (AT) of...
1. A volume of water was heated to 83.90 °C and immediately added to 48.11 mL of water at 23.98 °C contained within a coffee cup calorimeter. The final temperature of the mixture was 40.86 °C. The final volume of water inside the calorimeter was 90.45 mL. Assuming that them heat capacity of the solution is 4.18 J/g/°C, calculate the following: a. The volume of hot water added ml b. The mass of hot water (dwater = 1.00 g/mL) c....
1. A volume of water was heated to 81.76 °C and immediately added to 48.80 mL of water at 20.55 °C contained within a coffee cup calorimeter. The final temperature of the mixture was 37.73 °C. The final volume of water inside the calorimeter was 92.03 mL. Assuming that them heat capacity of the solution is 4.18 J/g/°C, calculate the following: a. The volume of hot water added ml b. The mass of hot water (dwater = 1.00 g/mL) g...
100 mL of a 0.2 M solution of NaOH is mixed with 150 mL of a 0.3 M HCl solution. A neutralization reaction occurs: NaOH + HCl —> NaCl + H2O. What is the molarity of the molecules in the mixed solution after the reaction has reached completion?
An aqueous solution of HCl is added to an aqueous solution of NaOH in a coffee cup calorimeter. The reaction is that of neutralization between the acid and the base: HCI + NaOH → H20+ NaCl To calculate the approximate enthalpy change for this reaction using q = m. C-AT, what value should the student give to C in the equation? The student must use the heat of formation of water. The student must use the heat of formation of...
An aqueous solution of HCl is added to an aqueous solution of NaOH in a coffee cup calorimeter. The reaction is that of neutralization between the acid and the base: HCI + NaOH + H2O + Naci To calculate the approximate enthalpy change for this reaction using q = m-C-AT, what value should the student give to C in the equation? The student must use the heat of formation of water. The student must use the heat of formation of...
reaction one NaOH and HCl. 50.0 mL of 2.0 M HCl solution into
50.0 mL of 2.0 M NaOH
reaction two 50 mL OF 2.0 M NaOH into 50 mL of 2.0 M NH4Cl
reaction three 50.0 mL of 2.0 M HCl into 50.0 mL NH3
pleanse answer all of the questions
Experinen DATA TABLE Reaction 1 Reaction 2 Reaction 3 34,012。21 2H0 Maximum temperature (C) Initial temperature (C) Temperature change (&T) DATA ANALYSIS 1. Calculate the amount of heat...