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need help, tried to work theough problem but can't. this is calculating ph of base solutions openstax chap 14.3


Write a balanced chemical equation for the dissociation of calcium hydroxide: Calculate the pH of a 0.122 M solution of calci
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cacoH), (aq) → cat (aq) + 204 (aa) ph ot solution is defined as -los.CHE] PH. – los CH) pH + por = 14 pOH = -los, como CaCOH)= - - ( los 2.444 105). - Clog,.2:44 - 1.199,1) 1-109,2.44 21-0.38 = 0.62 pol = 0.6 ol p + P = 14 - pH = 14-polt = 14-0.6

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