Question

5. Interpret the titration curve below- mark the points and find the values: (10 points) a. Equivalence point b. pH value at equivalence point c. volume at equivalence point d. 1 Equivalence point e. pH value at /2 equivalence point f. volume at 12 equivalence point 5.0 30.0 10.0 15.0 20.0 25.0 Volume of 0.100 M NaOH, mL

Can you label all these points on the graph, and if you don't want to draw the graph it's okay just tell me the x and y points for A. though F. Thank you!

Answer 1

In given graph, there are two equivalence point, that may be due to titration of base with acid of H2A type, weak diprotic acid e.g. H2SO3 a)- Equivalence point- equivalence point is the point in a titration where the amount of titrant added is enough to completely neutralize the analyte solution. b) & c) - 1st equivalence point - at pH 5, vol of base added at 1st equivalence point - 10mL 2nd equivalence point - at pH 10.5, vol of base added at 2nd equivalence point - 20mL d)- half Equivalence point- The half-equivalence point of an acid-base titration is the point at which the concentration of an base added is equal to half of the original concentration of the acid. The half-equivalence point is also known as the midpoint of a titration. e) 1st half-equivalence point - at pH 2.1 2nd half equivalence point - at pH 7.5 f) - vol of base added at 1st half equivalence point - 5mL vol of base added at 2nd half equivalence point - 10mL