Question

Question 8 (1 point) If 248.9 g of methane gas (CH4) is reacted with 306.1 g of steam (H20 (g)) to produce hydrogen gas and carbon monoxide gas, then what is the maximum mass in grams of hydrogen gas that can be produced? CH4(8) + H2O(g) + 3H2(g) + CO(g) Report your answer to 2 decimal places. No marks for units. Your Answer: Answer units Question 9 (1 point) Nitrogen gas reacts with hydrogen gas to produce ammonia gas (NH3). Suppose 3.030 g of nitrogen gas are reacted with 4.100 g of hydrogen gas. If 1.32 g of ammonia is actually produced, then what is the percentage yield of ammonia? N2(g) +3H2(g) - 2NH3(g) Report your answer to 2 decimal places. No marks for units. Your Answer: Answer units

Answer 1

Soluton to the given question is shown in the below images

98) Moles of GHy = fiven Mass 248.9 - 15.556 moles Molar Mass 16 Cleo Moles of H2O = fiven Maso - 306.1 - 17.005 moles Molar Mass 18 C GHulg) + H₂O(g) 3H₂(g) + 60(g) Intial 15.556 17.005 0 0 Final 15.556-c 17-005-30 300 C If GHy is limiting reagent 15.556 - 36 =0 => 3c=15.556 • If H₂O is limiting reagent 17.005-30 = 0 => OC = 17-005 From where we get smaller value of so, that compound will be limiting reagent: Therefore CH4 có limiting reagent and c = 15.556 Moles of H2(g) produced = 30c = 3x15.556 = 46.668 moleso Maso of H219) produced = Moles x Molar Mass of Hz = 46.668 x2 = 93.3375 g ñ 93.349

28 lass 99) Moles of Ny = Given Mass 3.050 - 0.1082 moles 1 Molar Mass Moles of Hz = given Mass = 4.100 = 2.05 moles Molar Mass 2 Nalg) + 3H2(g) → 2 NHz (9) Intial 0.1082 2.05 0 Final 0.1082-06 2.05-30 30 • If Ny is limiting reagent 0.1082-9C =0 => 3C = 0-1082 • If H₂ is limiting reagent 2.05- 3x = 0 => 3C = 0.683 Erom where we get Smaller value of so, that combound will be limiting reagent. Therefore Nz is limiting reagent and oc = 0.1082 Moleo of ammonia(NH3) produced - 320 = 5x0.1082 = 0,-3246 moles theoretically Mass of ammonia(N145) produced. - Moleso x Molar Mass of NH3 theoretically 3-0.3246 x 17 = 5.51899 ñ 5.529 Percent Yield = Actual Yield +100 Theoretical Yield = 1.32x100 = 23.91%
Answers

• Q(8) - Mass of hydrogen gas(H2) produced is 93.34g.
• Q(9) - Percent yield of ammonia(NH3) is 23.91%