Question

how much NaAl02 is required to produce 2.81 kg of Na3AlF6?

nment #13 03/30/20 all 70% This is a Numeric Entry question / It is worth 3 points / You have 2 of 3 attempts remaining/Ther 13 Question (3 points) The manufacture of aluminum includes the production of cryolite (Na3AlF.) from the following reaction: 6HF + 3NaAlO2 - Na, AlF6+3H,0+A1,03 1st attempt Feedback Iw See Periodic 1 How much NaAlO2 (sodium aluminate) is required to produce 2.81 kg of Na3AlF6? < 13/16 > • VIEW SOLUTION

Answer 1

6HF + 3NaAlO2 -------> Na3AlF6 + 3H2O + Al2O3

Stoichiometrically, 1mole of Na3AlF6 obtained by 3moles of NaAlO2

Number of moles = mass/molar mass

moles of Na3AlF6 required = 2810g/209.95g/mol = 13.384mol

moles of NaAlO2 required = (3/1) × 13.384mol = 40.152mol

mass of NaAlO2 required = 40.152mol × 81.97g/mol = 3291g = 3.291kg

Therefore,

Mass of NaAlO2 required = 3.291kg