Question

If the standard reduction potential for A --> A+ + e- was 1.21 volts and the standard reduction potential for B --> B+2 + 2 e- was 0.46 volts, what would be the standard potential for the following reaction: B+2 + 2 A --> 2 A+ + B?

If the standard reduction potential for X --> X⁺² + 2 e^- was 0.53 volts and the standard potential for the reaction: X + Y⁺² --> X⁺² + Y was 0.4 volts, what would be the standard reduction potential for: Y --> Y⁺² + 2 e^-?

What element is undergoing oxidation in the following reaction: Cr₂O₃ + Al --> Al₂O₃ + Cr

Which element is undergoing reduction in the following reaction: FeF₂ + CrF₃ --> CrF₂ + FeF₃? (Give the name.)

Answer 1

oues 2222222 a o g²+ + 2A t é Bettzé QAT+B Eu 1.21 v = 0.46 E = ? Solution e canderd o sincer electrode potential is intensive 3 proporty , therefore it is not additive. • • Gibb's free energy is extensive . property, there it is additive. B. We will perform the calculatious of • electrode potentiale in terms of асьЬ's pse ayag STEP O log -- FI where og . Gibb's free energy in a Standerd state. na Mo of electrons participate po = standerd electrode concidation/ Reductions potentials

Given that A at t é ti = 10210 Here = 7 Let Gibb's free energy og, = - nf El => ag, = -1 xfxfi multiplying by 2 in both side of above equation : 2A 2At trè B EO (het) u 2, het here Gibb's free enero 1952-2713230 comparing equation of B 2x AG = 42 - 2X (-1XFXE = + 2 xf Ej = 12 = 12V -

(het) Now B - B²+ tre o E = o.uGuia Reversing this equation : 7 B²+ trê BED E 8 = -0.46N 13=2 ст-Р (2) 2A 2Attre ® E 2 = 10210 882 n2=2 & B 6 Es = -0.46 v 453 ng=2 BA+B? → AT TB na 9 + an=2 Honce na = 0 + 043 G = - nafar & nof Ego 2xFX (-0.46) " – 2FE - - 2xr (1.21 - = -5o = - 10 21 +0.46 - 6° = 1.21 -0.46 = 10.75 l Answer .

E aius x x² + trêt = 0.53v Oglannaf Ei & x+y +2+ + y = 0uur I y - y2+ tzł = ? Reversing equation number ) :- x2+ ty t y 2+ EO = -0.40 Mow dding equation 6 e @ :- x x 2t tré E = 0.53v. ni=2 106,=ch, foi xtyet a Es=-00 UN 2t 2+ ty laor= -h2FE2 2+ Y y tre Hence AG=anFE n=2 lay = -2 RE -

7 + 092 09 -) enfeit (haft - 26% -) - 2(0-53) + 12 F*(-0.44 ] = 426 € - 0.53+0.4 = -6° -) FO = +0.53 -0.4 - Answer • Ques ♡ +30 + A . A . Og ter +3 • Oxidation means inerease in osüdation number or removal of election. ein above choolding oxidation 2n+(-63 = 0 -| 2* = +6] => 1* = +31 • Onüdation state of one cr atom shange from +3 o czero) Thus it is not onüdized

of Al moves from • But onudation state wio to to. Thus 'All is undergoing oncidation. - Answer +2 Fefa +2 +3 t + 3 ex fg - Csf 2 tret3 Let we choch onidation state of metals- crct2) FeFQ Fe (+2) crf3 crct 3) Cyfr Fe F3 Fe (+3) since decreasing in oxidation Stecte is called reduction • It is clear that onidation state of chromium in chromium tri fluoride is decreasing it undergoes reduction • Hence Co Facchromium trifluoride - undergo reduction. Answer Hence