Determine the value of K for the balanced reaction, 2 NOCl(g) ↔ N2(g) + O2(g) +...

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Determine the value of K for the balanced reaction, 2 NOCl(g) ↔ N2(g) + O2(g) +...

Determine the value of K for the balanced reaction, 2 NOCl(g) ↔ N₂(g) + O₂(g) + Cl₂(g) at 279 K

2 N₂(g) + 2 O₂(g) ↔ 4 NO(g); K = 6.503×10^-62

NO + 1/2 Cl₂(g) ↔ NOCl(g); K = 4.122×10⁴

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Answer 1

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2 N₂ +20 (9) loi + 4NO (9) K = 6.503 41062 - [NO] -62 = 6.503 X10 EN, J² 203 [Na]*293² [No34 6.503 x1062 square root on both -1 [no] *Ecl.] . [nocl}? [no] [cly I Nocl] Enog2 {cl (4:122 X164) ² ] . x168 = = (4-122 X 4-122) - 0.058855x108 E [nool² [Noo

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