Question

1. How many moles of NaBr will be produced by the following reaction in each case? Na(s) + Br2() →NaBr (s) a. 1 mol Na and 0 mol Br2 b. 2 mol Na and 1 mol Br2 c. 3 mol Na and 1 mol Br2

Answer 1

Here the green equation is it 2 Ma CSI + Bralel Na Br (5) Here amole of na react with Imole of Bro. @ In this past I mol of Na and omol of Bra ginen. 1. because there is o mol of Bry so the reaction bill not occur, so omol of NaBr will fireduce o in this fant a mol of Na and Imol of Bra Jiren. 2 mol of na react with Imol of Bra and produce amol of Maßr. so in this fant amal of NaBr will produce. wines @ In this past 3 molina and imol Bro ginen - amol of Na react with Imal of Bra so 3 mol of Na will react with Ix3 mol of Bra L = 1.5 mol of Bra but we have only I mol of Bra so Bra in a limiting reagent, so reaction will knoceed arenting- + २ . - Imol of Bracel proceed 2 mol of NaBr so here also amor of Na Br will produce. Scanned with CamScanner