Question

im having trouble with #4

molsolute -I = I solution 3. Calculate the moles and grams of NH OH present in 30.0 mL of a 1.50 M NH OH solution. (See the molarity formula.) O 30.0 L = 10.145 moll IL soln = 1.577 0.045 mol NHg Ott 135.otleg NipH 1 Imolto Hot 4,5810-2 mol - 1.58. 4. Would the 30.0 mL of 1.50 M NH OH from problem 3 be sufficient to react with 4.2 g of CuSO4.5H2O? Show supporting calculations and explanation. 5. How does the color of the clear supernatant indicate to you that copper (II) sulfate is NOT in excess?

Answer 1

yes it is sufficient to react with it. As it has higher moles than CuSO4.H2O

u moles of wsoy. 5H₂O = 4.2 249.5 - 0.0168 ml moles of Whyol vous molx