1 mole of P4 gives 4 moles of PH3 as per balanced reaction
Hence Blank 1 will be 1 and Blank 2 will be 4
6 mole of H2 gives 4 moles of PH3 as per balanced reaction
Hence Blank 3 will be 6 and Blank 4 will be 4
1 mole of P4 reacts with 6 moles of H2 as per balanced reaction
Hence Blank 5 will be 1 and Blank 6 will be 6
Note - Post any doubts/queries in comments section.
Question 1 P4 (s) + 6 H2(g) → 4 PH3(g) What are the correct mole ratios...
Consider the reaction 4 PH3(g) → P4(g) + 6 H2(g). If, in a certain experiment, over a specific time period, 0.0045 mole of PH3 is consumed in a 1.7-L container during each second of the reaction, what are the rates of production of P4 and H2 in this experiment? P4 mol L−1 s−1 H2 mol L−1 s−1
The decomposition of phosphine, PH3, follows first-order kinetics: 4 PH3(g) → P4(g) + 6 H2(g) Calculate the activation energy, Eq, in kJ/mol for the reaction, given that the rate constant k (at 25 °C) = 0.00852 s 1 and k (at 50 °C) = 0.756 s 1. 231 kJ/mol 144 kJ/mol O 56.5 kJ/mol О 99.3 kJ/mol O 111 kJ/mol
8. The balanced equation P4 (s) + 6H2 (g) --> 4PH3 tells us that 2 mol H2 a. reacts with 1 mol 4 b. produces 4 mol PH3 c. cannot react with phosphorus d. produces 2 mol PH3 e. reacts with 2 mol P4 idk y i cant seem to get the answer from the choices above?
Question 4 1 pts Which of the following mole ratios CANNOT be derived from the reaction 2 502 (g) + O2 (g) + 2 H20 (1) --> 2 H2SO4 (aq) ? 02 mol SO2 2 mol H2SO4 2 mol H2SO4 2 mol O2 0 1 mol O2 2 mol H20 O 2 mol O2 1 mol O2 2 mol H20 2 mol SO2 Question 1 1 pts What do the coefficients in a balanced equation tell us? Mark ALL that...
[14.117] The rate of the reaction 4 PH3() → P4(3) + 6 H2(8) was studied by charging PHz(8) into a constant-volume reac- tion vessel and measuring the total pressure. Time (s) 0 30 60 90 120 13.3 18.5 20.9 22.1 22.8 Determine the reaction order and also the rate constant for the reaction. total (kPa)
Question 1 --> 2NH3 Determine the correct mole ratios based on the following reaction: N2 + 3H2 N2:H2 [Choose H2: NH3 [Choose N2: NH3 [Choose]
3(20 pts) Consider the data: P4(s) + 6 Cl2(g) ----> 4 PC13(g) P4(s) + 5 O2(g) -----> P4010(s) PC13(g) + Cl2(g) ---> PCls(g) PC13(g) + 1/2O2(g) ----> C13PO(g) AH° (kJ/mol) -1226.6 -2967.3 -84.2 -285.7 Using only the above reaction data, compute the AHX of P4010(s) + 6 PCls(8) ----> 10 C13PO (g)
4. (10 points)Given the following data: P4 (s) + 6 Cl2 (g) -------> 4 PC13 (1) P4 (8) + 10 Cl2 (g) -------> 4 PCls (g) AG° = -1088 kJ/mole P4 AG° = -1292 kJ/mole P4 Calculate AGº for the reaction PC13 (1) + Cl2 (g) -------> PCI; (g) (answer only 1 point)
a) Calculate Kp for this reaction. (10 pts each) P4O10(s) + 16 H2(g) -> 4 PH3(g) + 10 H2O(g) -) Calculate AG if the amount of chemicals is adjusted to 5.6 g P.0.0, 2 atm H2, 0.35 atm PH3, and 0.58 atm water?
24 3 points Consider the reaction: Pa(s) + 6 H2() + 4 PH3(g) If 88.6 L of H2, measured at STP, is allowed to react with 158.3 g of P, which of the following are true? (select all that apply) Pe is the limiting reagent The theoretical yield is 48.3 L Hy is the limiting reagent The theoretical yield is 114L The theoretical yield is 59.1L The actual yield is 114 L