For the equilibrium: 2 SO3(g) < = > O2(g) + 2 SO2(g) Kp = 0.269 at...

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For the equilibrium: 2 SO3(g) < = > O2(g) + 2 SO2(g) Kp = 0.269 at...

For the equilibrium: 2 SO3(g) < = > O2(g) + 2 SO2(g) Kp = 0.269 at 625 oC

What is Kc at this temperature? Kp = Kc[RT]Δn R = 0.08206 L-atm/mol K

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Answer 1

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26039) 029)+ 2 802,69) Kp=0.269 on = no of ganeous products - no. of gaseous reactants E 3-2 R=0008206 L.atm/molik T= 625+273

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Answer 2

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For the equilibrium: 2 SO3(g) < = > O2(g) + 2 SO2(g) Kp = 0.269 at...

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For the equilibrium: 2 SO3(g) < = > O2(g) + 2 SO2(g) Kp = 0.269 at...

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2) For the equilibrium: 2 SO3(g) <=> O2(g) + 2 SO2(g) Kp = 0.269 at 625...

2) For the equilibrium: 2 SO3(g) <=> 02(g) + 2 SO2(g) Kp = 0.269 at 625...

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1. The equilibrium constant, Kc, is calculated using molar concentrations. For gaseous reactions another form of...

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For the equilibrium: 2 SO3(g) < = > O2(g) + 2 SO2(g) Kp = 0.269 at...

Homework Answers

Add Answer to: For the equilibrium: 2 SO3(g) < = > O2(g) + 2 SO2(g) Kp = 0.269 at...

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Add Answer to:
For the equilibrium: 2 SO3(g) < = > O2(g) + 2 SO2(g) Kp = 0.269 at...