Question

1. Consider a gas in a rigid container initially at 533 torr and 15.00 ^oC. What final temperature, in Kelvin, is needed to reduce the pressure to 342 torr? Use 273.15 for any Kelvin conversion steps. Round your answer to a whole number (ones place)

2. A gas initially at 2.40 atm and 311 K is cooled to 235 K at constant volume. What is the final pressure, in units of atm? Report your answer with two decimal places.

A gas initially at 627 torr is transferred at constant temperature to a 2.0 L container at 1.40 atm. What was the initial volume in Liters? Round your answer to the first decimal place.

Answer 1

IDEAL GAS EQUATION:

PV=nRT

Here, P is pressure

         V is volume

        n is number of mole

         R is gas constant ( 8.314 JK-1mol-1)

       T is temperature in kelvin

1)

Ideal gas equation at constant n and V :

$\frac{p_1}{T_1}=\frac{p_2}{T_2}$

Where,

                   T1 and P1 are the initial temperature and pressure respectively

                    T2 and P2 are the final temperature and pressure respectively

T1 =15+273.15)k=288.15K and P1=533 torr , T2 =? and P2=342 torr

533 Id ysost = yers it I <=

2)

T1 =311K and P1=2.40 torr , T2 =235K and P2=?

=> P = P412 - 2.40 x 235 torr = 1.81torr 311

3)

Ideal gas equation at constant n and T :

PIVA = P2V2

Where,

                   P1 and V1 are the initial pressure and volume respectively

                    P2 and V2 are the final pressure and volume respectively

P1 =627 torr and V1=?

P2 =1.40 torr and V2=2.0 L

P2V2 Vi = P = 1.40 x 2, 627 = L = 4.5 x 10-'L L