Question

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QUESTION 16 Look at the following equation: 3H2 + N2 -> 2 NH3 19.0 gram of N2 is reacted with excess H2 . We obtain 12.6 g of NH3. What is the percent yield of NH3? Hint: find theoretical yield Hint: percent yield =(actual yield/ theoretical yield) x 100 O 96.2 %. 0 40.3%. O 13.1%. O 54.6 %. O 85.2%. 0 75.4%. O 54.7 %. o 49.8%.

Answer 1

19om N2 malas mass of N2 a moles of N = = 28 gimol = 0.68 miles 28 n a 3H2 + N2 2013 1 mol Nz gives a mol NH3 so oo 60 mol niz will gine 2x0.68 = 1-36 mol NH3 molar mass of NH3 = 17 almal & theoritical yild of NH3 = 1.36x17= 23-lom actual yield of NH3 = 12.65lm of yield = 1206x100 = 54-6%. 8311 a (clo yield = 54-6%} CScanned with CamScanner