3.
Volume of water in the blood plasma = 5.0 (L) = 4.75 L = 4.75(L) = 4750 mL
density = 1.025 g/mL
then mass of water = volume density
= ( 4750 mL )
= 4869 g
= 4869 (g)
= 4.869 Kg
now
Henry's law equation is
Cg = KH Pg
given , Pg at 30 m depth = 4.154325 bar ; KH = 6.010-4 mol/kg bar
Then , concentration of N2 in mol/Kg is
Cg = 6.010-4 (mol/kg bar) 4.154325 (bar)
= 0.002492 mol/Kg
now, in 4.869 Kg of water moles of N2 present
= 4.869 (Kg) 0.002492 mol/Kg
= 0.01213
mass of N2 = moles molar mass = 0.01213 (mol) 28 (g/mol) = 0.340 g
= 0.340 (g)
= 340 mg
therefore mass of N2 dissolved in her blood at 30 m depth = 340 mg
again at sea level pressure ( Pg) = 1.01325 bar
now, Cg = 6.010-4 (mol/kg bar) 1.01325 (bar)
= 0.000608 mol/Kg
now, in 4.869 Kg of water moles of N2 present
= 4.869 (Kg) 0.000608 mol/Kg
= 0.00296
mass of N2 = moles molar mass = 0.00296 (mol) 28 (g/mol) = 0.0830g
= 0.0830 (g)
= 83 mg
now, total amount of N2 comes out
= (340 - 83.0) mg
= 257mg
then , percentage of N2 comes out from the solution when the driver surfaces ( at sea level)
=
=
= 75.6 %
3. The volume of blood plasma in an adult is 5.0 L, about 95% of which...