A 90 W electric blanket runs at 24 V .
Part A
What is the resistance of the wire in the blanket?
Express your answer to two significant figures and include the appropriate units.
Part B
How much current does the wire carry?
Express your answer to two significant figures and include the appropriate units.
The resistance is:
\(R=\frac{V^{2}}{P}=\frac{24^{2}}{90}=6.4 \Omega\)
The current is:
\(i=\frac{V}{R}=\frac{24}{6.4}=3.8 \mathrm{~A}\)
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