V = IR
=> R = V/I = 240V/7.10A = 33.8 ohms
Part A: Vnew = V × (1-0.35) = 0.65 × V = 0.65 × 240 V = 156 V
R = 33.8 ohms
Current (Inew) = Vnew/R = 156 V / 33.8 ohms = 4.615 A
Part B: Rnew = (1-0.35) × 33.8 = 21.97 ohms
V = 240 V
Inew = V/Rnew = 240 V / 21.97 ohms = 10.92 A
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