A 9.5 V battery supplies a 3.5 mA current to a circuit for 7.0 h ....
A 9.5 V battery supplies a 3.5 mA current to a circuit for 7.0 h .
Part A: How much charge has been transferred from the negative to the positive terminal?
Part B: How much electric potential energy has been gained by the charges that passed through the battery?
Homework Answers
I = Q/T
i.e ampere = coulomb / second
Now,
Part A: The amount of charge passed is:
Q = I * t = 3.5mA * 7h * 3600s/h = 88.2C
Part B: Electrical work is:
w = q * V = 88.2C * 9.5V = 837.9joule =838J
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A 9.5 V battery supplies a 3.5 mA current to a circuit for 7.0 h
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