Question

Ton 12 of 12 Attempt 1 A solution contains A18+ and Co2+. The addition of 0.3288 L of 1.813 M NaOH results in the complete precipitation of the ions as Al(OH), and Co(OH),. The total mass of the precipitate is 21.24 g. Find the masses of Art and Cot in the solution. mass of Allt: 3.15 mass of Co2 6.785 s p help racy policy terms of use contact us MacBook Pro

Answer 1

Mass of Al​​​​​3+ is 2.8373 g

Mass of Co​​​​​2+ is 8.2687 g

Details answer with stepwise given in the attachment.......

2+ A somation contains Alst and cont The addition of 0.3288 L of 10813 M NaOH result in the complete precipitation of the ions as ALCOHz and Co (OH)₂. The total mass of the precipitate is 21.24 9. Find the mass of A13+ and Co²t in the solution. Answer :- 0 - 3288 L 1.818 M for find volume NaOH. Total mass=21.249 mass of Al3+ and Co²+ 2 + mass A gone Steps sa Step-ot. Find we know moles of NaOH (sodium Hydroxide) molar mass of Naon = 39.9 g/mol 1.813 M Nooh means 1.813 moles of Naon in L solution. that is Step -02. we 1.813 M NaOH = 1.883 Moles - 1.2 Now for moles of oH get moles of ou 0.3288 L Naoh solution) & (1.813 moler NaoH) Imol on Ximol Noon - 0.5961144 mol OH-

Step-03 Now Calculate mass in g of Hydroxide Molar mass of Oh = 16+1 = 17 g/mol Dipos mass= (mol of oth ) x (modar mass) mass of our = (0.5961144 mod) x (17 / moe) mass of OH = 10.134 g Step-04 Now given total mass= 21.24 g that contains Al?t & Co²+ and on let mass of Al3+ = a mass of A Co²+ = 6 mas so Al3+ + Co 2 OH = 21.249. a+b + OH = 21.24 g Now in step 3 we get mass of on so 9+b = 21.24 g -10.134 g = 11.106 g. so we get a equation atb=11.106

2 + a. gram Al and begram Step-05 co to their of we find mod of our in step 02 = 0-0596114u mal on mol of Bound oh = (moles of oh band to A22 (moles of oH) Bond to con Bound) =0.5961144 mol on он 34 OH Step-06 Relationship of hydronide from formulas. Al(OH)₂ 1 mol Al = 3 mol on Co COM I mol cot = 2 mal oh using this a (mass of Al) Convert to a mol of Ort Bound to Al b (mass of co) Convert to b mol of Oh Bound to co for convesion molar mass of Al= 26.98 g , and Co= 58.93g. for Al (a g Al) x (1 mol Ad). - 0.1112 mol Out Bound 26.989 Al 1 mol Al to Al x 3 mol our For Co (6 g Co) x (1 Mol (o) x 2 mol ori - - - 0.0384 mol of 58.93 I Co 1 mol co Bound to Co

relation between a and Step-07 b from Step -os put the values we get 0.05961144 mol OHEG (oolll2 mol or bound to All +60-034 mol OH bound to So secound equation is : 9 0.1112 + 60.034 = 0.05961144 By using this two equation Le ① and ② we get a, and b. a+b= 11.106 a o.lll2 + 60.034 -0.0596 1144 on solving we get az 2.8373g = mass of Al 3+ b= 8.2687g a mass of Co2+ so mass of Alst - 2.8373 g ? mass of Colt - 8.2687 g