Question

What is the percent yield of if the reaction of 25.0 g P. and 91.5 g Cl2 produces 104. PCI P.(s) + Cl2(g) → PC13(1)
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Answer #1

P4 (8) + Goly (g) 4 Pcz (s) man of ly mole of ly tracted = 259 1 = max = 25g =0.201 mole molarman 124 ginal mole of a suacted

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