K Balanced equation:
MnO2 + 4 HCl ====> MnCl2 + 2
H2O + Cl2
Let us calculate the moles of Cl2 using following ideal gas equation
PV= nRT
P = Pressure in atm = 725 Torr = 0.953947 atm V= Volume in Liter = 275 ml = 0.275 Liter
n = no of moles = ? R = 0.08206 L atm K-1 Mol-1
T = Temperature in Kelvin = 298 K
n = PV / RT
n = 0.953947 atm x 0.275 L / 0.08206 L atm K-1 Mol-1 x 298 K = 0.01072 Moles
Moles of Cl2 produced = 0.01072 Moles
Moles of MnO2 required = 0.01072 Moles
Molar mass of MnO2 = 86.936 g/mol
Mass of MnO2 required = 0.01072 Moles x 86.93 g/mol = 0.9319 g
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