What is the molar concentration of 4.32 g phosphoglycerate (Mr = 216) in 250 ml expressed using metric prefixes? a) 80 x 10-2 mmol b) 8 x 10-2 mol c) 80 mM d) 8 x 10-2 mM = 80mM ... but I do not understand how the answer went from 0.08 to 80 mM in the question?
What is the molar concentration of 4.32 g phosphoglycerate (Mr = 216) in 250 ml expressed...
If you dissolve 412 mg sucrose (formula weight: 342.29 g/mol) in 60 mL of water: a. What is the concentration of sucrose in mM in µM? b. If you take 5 mL of this solution and dilute it to 250 mL, what is the concentration of the glucose in the resulting solution in µM? c. How many nano moles of sucrose are present in 10 mL of the diluted solution?
stuck on nimbers 5-10 that are blank. please help B. Molar Concentration of an Acid Solution Acid type, HA or H.A: PA Unknown No. mol NaOH =23 till mass mm + 40 mm Balanced equation for neutralization of acid with NaOH. 1. Volume of acid solution (mL) 2. Buret reading of NaOH, initial (mL) Sample 1 Sample 2 Sample 3 25.0 25.0 25.0 15.7mL 16. 2mL 16.7mL 39,8 ml 40.0mL 40.8ml 24.1mL 23.8mL 24.1mL mor & Avg= 24L 3. Buret...
I need help please. was titrated with a 1.00 x 10M EDTA solution. It took A 12.0 mL sample of water from a kitchen tap was titrated with a 1.00 x 102 MED 1.00 mL of the EDTA solution to change the indicator from red to blue. 1) What is the total number of moles of Ca* + Mg in the Swan Lake water sam Cake water sample? mmoles of EDTA 1.00.102.1.00m2 =1.00.102 mme Ca 2+ + m2tions = 1.00...
Lab Exercise IB Examples: 1000 is expressed as 1 x 10) (1000 is greater than (1000 is greater than 1, so the exponent is positive) tion of 1. so the exponent is negative) 0.001 is expressed as 1 x 10-3 (0,001 is a fraction of 1 Note: you cannot just count the number of Os, you ne need to count the number of places th decimal moves to make the coefficient be greater Now lets combine all 3 rules: 0.00000000000308...
A. Determination of Reaction Times Molar concentration of Na,s,0, 0 Volume of Na,S,0,(L). Ambient temperaure c Molar concentration of KI 02Molar concentration of ,O, Total volume of kinetic trials (mL) _IO m Kinetic Trial 1. Time for color change, At (sec) 0s 353s 755 B. Calculations for Determining the Rate Law 1. Moles of s,0,2 -5 consumed (mol) O 20 么Drio 2. A(mol I) produced (moll) (mol/s) Δι Δ(mol 13-) 4. log At 5. Volume KI (mL) 6. IIlo (moU/L)...
What is the concentration of an AlBrz solution if 150. mL of the solution contains 250. mg of Brion? OA) 1.67 M OB) 6.23 * 10-3 M C) 2.08 x 10-2 M OD 6.95 x 10-3M
A 25.00 mL sample of 0.685 M cobalt (II) phosphite (X) a. has a molar mass of 105.9064 g/mol b. has a molar mass of 105.906 g/mol 4. contains 1.8*10 g CX) contains 6.280 g contains 6.28 g CX) contains 6.3 g contains 5.732 g CX) contains. contains 5.l g contains 4.380 g CX) contains 4.38 g( contains 4.4 g contains 1.814 g CX) contains 1.81 g CX) contains 1.8 g (X) contains 2 PO4 ions contains 6 PO4 ions...
what is the theorical value of dibenzalcetone? CIziceLUna. NAOH, HO, Hас сн, +2 CH3CH2OH Acetona Masa molar 58 g/mol Densidad: 0.79 g/mL Reactivo limitante Benzaldehido. Masa molar 106 g/mol Densidad 1.04 g/mL Se usará un exceso. Carbonos originales de acetona Dibenzalcetona Masa molar 234 g/mL Punto de fusión entre 80 y 120° C reaun, rigu, Hас- сн, +2 H CH-CH-он Acetone molar mass: 58 gmol density: 0.79g/mL limiting reagent Benzaldehyde molar mass: 106 g/mol density: 1.04 gmL an excess will...
2. A student prepared a stock solution by dissolving 15.0 g of NaOH in enough water to make 150 mL of a stock solution. She then took 22.5 mL of the stock solution and diluted it with enough water to make 250. mL of a working solution. (5 pts. each) A. What is the molar concentration of NaOH in the stock solution? # of moles x 1000 Naot mass= 15,09 g molanty volume of source (m) Mol 40 g/mol voline...
4. (a) Determine the experimental concentration of protein in the unknown solution in mg/mL using the Part II Data Table and the equation on page 2 for the absorbance assay at 280 nm. Hint: Convert the molar concentration (M or moles/liter) of BSA from absorbance assay at 280 nm method to mg/mL, assume that the molecular weight of BSA = 66.5 kDa [7 points 6500 g/mol Post-lab 10 Report Form: Determination the Concentration of a Protein You must show your...