If a base has Kb = 4.09 x 10-8, the value of Ka for the conjugate acid is___________________
The required answer is 2.44 * 10-7 .
EXPLANATION -
Let the base is given by B.
Kb for the base will be given by
[It is assumed that the concentration of water does not change much, so it is excluded.]
BH+ is the conjugate acid.
Now the conjugate acid has its own equilibrium.
Ka for the conjugate acid will be given by
= 2.44 * 10-7
So the required answer is 2.44 * 10-7 .
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