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Here, the relation between conc. and abs. is linear.
Let the for absorbance as , A = mC + C'
Here, A is absorbance , C is concentration, m and C' are constants.
Calculate the value of m from table as follows:
m = (0.69 - 0.55)/(0.5 - 0.4) = 0.14/0.1 = 1.4
Then relation is A = 1.4C + C'
For C = 0.5, A = 0.69 then
0.69 = 1.4*0.5 +C'
C' = - 0.01
Then the relation is A = 1.4C - 0.01
Put A = 0.6 then
0.6 = 1.4C -0.01
1.4C = 0.61
C = 0.4357
Therefore, the required concentration is 0.4357.
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