Question

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1. Determine the mole %'s of methanol and water in a sample with 10.0g of water and 25.0g of methanol

Answer 1

Step2iGiven in solution Step 1 :- Formula Mole Percent of Methanol = ₂ OH x 100 "(W206+ H2O Mile Percent of H₂O = H₂O x100 . . nheo thCHzoh H₂o= water - methanol ..n = Number of Moles. Definition :- so, Mole percent is the number of roles of a particular component divide by the total number of Moles taken in mixture. 'Given ;- log H₂o and 25g CH₂ OH Molecular mass of H₂O = 18 gmont Molecube mass of CH, OH = 32 g moll Inumber of Moles = given mars Molenlere Mass | 9, - 18 I put these MCH ₂ OH = 2 = 0.781 mol l values in above formular 0 181 x 1070 - 58.07 Mole 1, CH2 CHE 0.781 +0.55 Hos 0.55 X 180 = 41.33 0.5570-T81 mole / CH ₂ OH= 58-67] Mole l. 4,o= 41-33 i step3 :- " 22